AngularJS实现ajax请求的方法
(编辑:jimmy 日期: 2024/11/19 浏览:3 次 )
本文实例讲述了AngularJS实现ajax请求的方法。分享给大家供大家参考,具体如下:
【HTML 代码】
<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width,user-scalable=no, initial-scale=1"> <link rel="stylesheet" type="text/css" href="" /> <title>angularjs实现 ajax</title> </head> <body ng-app="HelloAjax"> <div ng-controller="HelloAjax"> <form> <input type="text" ng-model="username" /> <input type="text" ng-model="email" /> </form> <table> <tr ng-repeat="user in users"> <td>{{user.username}}</td> <td>{{user.email}}</td> </tr> </table> <button ng-click="get_more();">get more</button> </div> </body> <script type="text/javascript" src="/UploadFiles/2021-04-02/angular.min.js">【js代码 ajax.js】
var myModule = angular.module("HelloAjax",[]); myModule.controller("HelloAjax",["$scope","$http",function HelloAjax($scope,$http){ /* $scope.users=[{'username':"zhangsan","email":"zs@11.com"}, {'username':"zhangsan2","email":"zs@22.com"}, {'username':"zhangsan3","email":"zs@33.com"}]; */ $scope.get_more = function(){ $http({ method: "POST", url: "./ajax.php", data:{'username':$scope.username, 'email':$scope.email } }). success(function(data, status) { //$scope.status = status; $scope.users = data; }). error(function(data, status) { //$scope.data = data || "Request failed"; //$scope.status = status; }); } }]);【PHP代码 ajax.php】
<"php://input"); $user = json_decode($data); //查询数据库 $conn = mysql_connect("localhost","root",""); mysql_select_db("test"); $sql ="select username,email from users "; $res = mysql_query($sql,$conn); $users = array(); while($row = mysql_fetch_assoc($res)){ $users[] = $row; } //当然这里简化了插入数据库 $users[] = array('username'=>$user->username, 'email'=>$user->email); //返回数据库 echo json_encode($users);更多关于AngularJS相关内容感兴趣的读者可查看本站专题:《AngularJS入门与进阶教程》、《jQuery常用插件及用法总结》、《jquery中Ajax用法总结》、《JavaScript中ajax操作技巧总结》及《PHP+ajax技巧与应用小结》
希望本文所述对大家AngularJS程序设计有所帮助。
下一篇:js数组操作方法总结(必看篇)