python爬虫 基于requests模块的get请求实现详解
(编辑:jimmy 日期: 2024/11/15 浏览:3 次 )
需求:爬取搜狗首页的页面数据
import requests # 1.指定url url = 'https://www.sogou.com/' # 2.发起get请求:get方法会返回请求成功的响应对象 response = requests.get(url=url) # 3.获取响应中的数据:text属性作用是可以获取响应对象中字符串形式的页面数据 page_data = response.text # 4.持久化数据 with open("sougou.html","w",encoding="utf-8") as f: f.write(page_data) f.close() print("ok")
requests模块如何处理携带参数的get请求,返回携带参数的请求
需求:指定一个词条,获取搜狗搜索结果所对应的页面数据
之前urllib模块处理url上参数有中文的需要处理编码,requests会自动处理url编码
发起带参数的get请求
params可以是传字典或者列表
def get(url, params=None, **kwargs): r"""Sends a GET request. :param url: URL for the new :class:`Request` object. :param params: (optional) Dictionary, list of tuples or bytes to send in the body of the :class:`Request`. :param \*\*kwargs: Optional arguments that ``request`` takes. :return: :class:`Response <Response>` object :rtype: requests.Response
import requests # 指定url url = 'https://www.sogou.com/web' # 封装get请求参数 prams = { 'query':'周杰伦', 'ie':'utf-8' } response = requests.get(url=url,params=prams) page_text = response.text with open("周杰伦.html","w",encoding="utf-8") as f: f.write(page_text) f.close() print("ok")
利用requests模块自定义请求头信息,并且发起带参数的get请求
get方法有个headers参数 把请求头信息的字典赋给headers参数
import requests # 指定url url = 'https://www.sogou.com/web' # 封装get请求参数 prams = { 'query':'周杰伦', 'ie':'utf-8' } # 自定义请求头信息 headers={ 'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36', } response = requests.get(url=url,params=prams,headers=headers) page_text = response.text with open("周杰伦.html","w",encoding="utf-8") as f: f.write(page_text) f.close() print("ok")
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