python判断列表的连续数字范围并分块的方法

from itertools import groupby

lst = [1, 2, 3, 5, 6, 7, 8, 11, 12, 13, 19]  # 连续数字

fun = lambda x: x[1]-x[0]
for k, g in groupby(enumerate(lst), fun):
  l1 = [j for i, j in g]  # 连续数字的列表
  if len(l1) > 1:
    scop = str(min(l1)) + '-' + str(max(l1))  # 将连续数字范围用"-"连接
  else:
    scop = l1[0]
  print("连续数字范围：{}".format(scop))

# 冒泡排序(从小到大)
lst = [4, 2, 1, 5, 6, 7, 8, 11, 12, 13, 19]

for i in range(len(lst)):
  j = i+1
  for j in range(len(lst)):
    if lst[i] < lst[j]:
      x = lst[i]
      lst[i] = lst[j]
      lst[j] = x
print("排序后列表：{}".format(lst))