python 计算两个日期相差多少个月实例代码
(编辑:jimmy 日期: 2024/11/30 浏览:3 次 )
近期,由于业务需要计算两个日期之前相差多少个月。我在网上找了很久,结果发现万能的python,居然没有一个模块计算两个日期的月数,像Java、C#之类的高级语言,都会有(date1-date2).months的现成方法,觉得不可思议。说句实在的,一直觉得python 的日期处理模块真心不好用。
哦,对了,别跟我说 datetime, calendar, dateutil 这些模块,因为我都试过了,都没用。有个竟然算出来还有错。datetime.timedelta只能计算出日时分秒。对年月却不支持。网上一搜,一大堆的。
dateutil.rrule这个例子是我好不容易找到的,请看我的测试结果:
import datetime from dateutil import rrule d1 = datetime.date(2016, 2, 29) d2 = datetime.date(2019, 3, 31) months = rrule.rrule(rrule.MONTHLY, dtstart=d1, until=d2).count() print(f"months={months}")
看到这样的结果,我只能呵呵了。
废话不多少,献上自己写的代码:
该代码返回,(月,小数月)
import datetime import calendar as c d1 = datetime.date(2016, 2, 29) d2 = datetime.date(2019, 3, 31) def calmonths(startdate, enddate): # 计算两个日期相隔月差 samemonthdate = None try: samemonthdate = datetime.date(enddate.year, enddate.month, startdate.day) except Exception as e: print(e) samemonthdate = datetime.date(enddate.year, enddate.month, c.monthrange(enddate.year, enddate.month)[1]) holdmonths = 0 decimalmonth = 0.0 if samemonthdate > enddate: premanthdate = None try: premanthdate = datetime.date(enddate.year, enddate.month - 1, startdate.day) except Exception as e: print(e) premanthdate = datetime.date(enddate.year, enddate.month - 1, c.monthrange( enddate.year, enddate.month - 1)[1]) currmonthdays = (samemonthdate - premanthdate).days holdmonths = (premanthdate.year - startdate.year ) * 12 + premanthdate.month - startdate.month decimalmonth = (enddate - premanthdate).days / currmonthdays elif samemonthdate < enddate: nextmonthdate = None try: nextmonthdate = datetime.date(enddate.year, enddate.month + 1, startdate.day) except Exception as e: nextmonthdate = datetime.date(enddate.year, enddate.month + 1, c.monthrange( enddate.year, enddate.month + 1)[1]) currmonthdays = (nextmonthdate - samemonthdate).days holdmonths = (samemonthdate.year - startdate.year ) * 12 + samemonthdate.month - startdate.month decimalmonth = (enddate - samemonthdate).days / currmonthdays else: holdmonths = (enddate.year - startdate.year ) * 12 + enddate.month - startdate.month return holdmonths, decimalmonth months = calmonths(d1, d2) print(f"months={months}")
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