layui实现根据table数据判断按钮显示情况的方法

<script type="text/html" id="barDemo">
  {{# if(d.status ==0){ }}
  <a class="layui-btn layui-btn-mini" lay-event="examine">查看</a>
  <a class="layui-btn layui-btn-mini" lay-event="edit">编辑</a>
  <a class="layui-btn layui-btn-danger layui-btn-mini" lay-event="del">删除</a>
  <a class="layui-btn layui-btn-mini" lay-event="submit">提交</a>
  {{# }if(d.status ==2) { }}
  <a class="layui-btn layui-btn-mini" lay-event="examine">查看</a>
  <a class="layui-btn layui-btn-mini" lay-event="export">创建组套产品</a>
  {{# }if(d.status ==1) { }}
  <a class="layui-btn layui-btn-mini" lay-event="examine">查看</a>
  {{# } }}
</script>